How do you find the zeros of 16x 4 81?
How do you find the zeros of 16x 4 81?
Precalculus Examples Solve for x . Add 81 81 to both sides of the equation. Divide each term by 16 16 and simplify. Divide each term in 16×4=81 16 x 4 = 81 by 16 16 .
What is the factor of x2 8x 16?
=(x−4)(x−4)
What are the factors of 16x 4 81?
Rewrite 16×4 16 x 4 as (4×2)2 ( 4 x 2 ) 2 . Rewrite 81 as 92 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 – b 2 = ( a + b ) ( a – b ) where a=4×2 a = 4 x 2 and b=9 . Simplify.
What is the factor of 81 and 16?
Therefore, the GCF – greatest common factor of 81 and 16 is 1.
What is the factor of 16x 4 81?
What are the zeros of 100X² 81?
-9/10 and 9/10 are the two zeroes of the given polynomial 100X²-81.
Can you factor 16x 2 25?
1 Answer. The answer is: (4x−5)(4x+5) . This polynomial is a difference of squares, and there is this formula to factor: a2−b2=(a−b)(a+b) .
What is a factor of 16 and 8?
8
The factors of 8 and 16 are 1, 2, 4, 8 and 1, 2, 4, 8, 16 respectively. There are 3 commonly used methods to find the GCF of 8 and 16 – long division, prime factorization, and Euclidean algorithm.
What is the GCF to factor 8x and 16?
The common factors for 8,16 are 1,2,4,8 1 , 2 , 4 , 8 . The numbers do not contain any common variable factors. The GCF (HCF) of the numerical factors 1,2,4,8 1 , 2 , 4 , 8 is 8 .
What are the factors of 16 and 81?
The gcf of 16 and 81 can be obtained like this: The factors of 16 are 16, 8, 4, 2, 1. The factors of 81 are 81, 27, 9, 3, 1. The common factors of 16 and 81 are 1, intersecting the two sets above.
Whats the GCF of 16 and 81?
The gcf of 81 and 16 can be obtained like this: The factors of 81 are 81, 27, 9, 3, 1. The factors of 16 are 16, 8, 4, 2, 1. The common factors of 81 and 16 are 1, intersecting the two sets above.
What are factors of 81?
No, 6 is not a factor of 81 since the factors of 81 are 1, 3, 9, 27, and 81.
How do you find the quadratic polynomial?
The steps to find the quadratic polynomial are as follows:
- Step 1: Find the sum of the two roots. Sum of roots = -4 + 2 = -2.
- Step 2: Find the product of the two roots. Product of roots = -4 * 2 = -8.
- Step 3: Substitute these values in the expression x2 – (sum of the roots)x + (product of the roots).
How do you find the zeros of a quadratic polynomial?
Hint: A quadratic equation is represented by $p(x) = a{x^2} + bx + c$, where a, b, c are the coefficients. To find the zeros of the quadratic polynomial, equate $p(x) = 0$.
Which of the following is the binomial factor of 16x 2 40x 25?
=(4x+5)2.
